Help me fast please give the coordinates(enclose the coordinates in parentheses) of the
foci, vertices, and convertices of the ellipse with equation x²/169 + y²/25 = 1

If we compare this to the general expression for an ellipse given by:

We can see that the vertex is

And we can find the values of a and b like this:

in order to find the foci we can find the value of c

The two focis are (12,0) and (-12,0)

The convertices  for this case are: (13,0) and (-13,0) on the x axis

And for the y axis (0,5) and (0,-5)

Step-by-step explanation:

For this problem we have the following equation given:

If we compare this to the general expression for an ellipse given by:

We can see that the vertex is

And we can find the values of a and b like this:

in order to find the foci we can find the value of c

The two focis are (12,0) and (-12,0)

The convertices  for this case are: (13,0) and (-13,0) on the x axis

And for the y axis (0,5) and (0,-5)

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2