Ax = bx + 1. How is the value of x related to the difference of a and b?

x = 1/(a-b)

Step-by-step explanation:

The given equation is ax = bx + 1

Collecting like terms:

ax - bx = 1

Factorizing x out of the equation:

x(a - b) = 1

Dividing both sides by (a - b):

Therefore, x is related to the difference of a and be by the equation

x = 1/(a-b) where a - b is the difference of a and b

angle addition postulate

2x=56

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°