Pls answer this asap

B. 254.3 miles

Step-by-step explanation:

If the plane had to return to the airport making a direct flight, all the 3 distances travelled would make up a triangle as shown in the attachment below.

Let x be the distance to travel back to the airport. This unknown distance (x) can be calculated using the Law of Cosines, which is, a² = b² + c² − 2bc cosA

Where,

a = x

b = 160 mi

c = 150 mi

A = 110.167°

Plug in the above values to solve for x

x² = 160² + 150² - 2(160)(150)*cos(110.167)

x² = 25600 + 22500 - 48000*(-0.345)

x² = 48100 + 16560

x² = 64660

x = √64660

x = 254.28

x ≈ 254.3 miles.

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4