What is the slope of A line that passes through the points (−1, 2) and (3, 10)

2

Step-by-step explanation:

(x¹, y¹) (x², y²) = (-1,2) (3,10)

Slope = (y²-y¹) ÷ (x²-x¹)

= (10 - 2) ÷ (3 -(-1))

= 8 ÷ 4

= 2

its kind of blurry. can you put a clearer pic?

step-by-step explanation:

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west