The length of a rectangular field is twice its breadth. If the area of the rectangular field is 98 sq. M., then what is the perimeter of the field? Also find the approximate length of the diagonal of the field.

Step-by-step explanation:

The Area of the rectangular field is expressed as A = LB and its perimeter

P = 2(L+B)

L is the length of the rectangular field

B is the Breadth of the rectangular field

If the length of a rectangular field is twice its breadth i.e L = 2B and the area is 98m² then;

98 = LB

98 = 2B*B

98 = 2B²

B² = 98/2

B² = 49

B = √49

B = 7m

if B = 7m

L = 98/B

L = 98/7 = 14m

The perimeter of the field P = 2(L+B)

P = 2(14+7)

P = 2*21

P = 42m

The perimeter of the field is 42m.

The length of the diagonal of the field can be expressed using Pythagoras theorem.

d = √L²+B²

d = √14²+7²

d = √196+49

d = √245

d = 15.7m ≈ 16m

Hence, the approximate length of the diagonal of the field is 16m

step-by-step explanation:

too many. (jk)

31 v bucks

step-by-step explanation:

since you bought 25 on friday and 6 on tuesday, you can just add them up.

25+6=31

check your work.

31-6=25

i hope this !

-yand3r3