A normally distributed population of package weights has a mean of 63.5 g and a standard deviation of 12.2 g. XN(63.5,12.2) a. What percentage of this population weighs 66 g or more

The percentage  is  %z %    

Step-by-step explanation:

From the question we are told that

     The mean is  

     The  standard deviation is  

      The  random number is  x  = 66 g

Given the the population is normally distributed

   The  probability is mathematically represented as

Generally the z-score for this population is mathematically represented as

  So

Now the z-value for 0.2049 from the standardized normal distribution table is  

=>      

The  percentage  is

     % z      

     %z   %    

the distance between point a and point b is 6 units

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p