1. A survey shows that 15% of nurses are being underpaid in a hospital that employs 200 nurses. (i) Construct a 90% confidence interval to represent the proportion of underpaid nurses in the hospital. Give an interpretation of this interval. [4] (ii) Suppose that in another hospital, 12% of the 120 nurses employed are underpaid. Construct a 90% confidence interval for the difference in proportions of nurses being underpaid at both hospitals. [4]

(i) Interval for proportion of underpaid nurses: 0.15 ± 0.0415.

(ii) Interval for difference in proportion: 0.03 ± 0.0641

Step-by-step explanation: Confidence Interval for a representation of the proportion is calculated by:

± z.

(i) is the proportion, in this case, of underpaid nurses: = 0.15

Confidence Interval is 90%, so z = 1.645

The interval is:

0.15 ± 1.645.

0.15 ± 1.645*0.0252

0.15 ± 0.0415

Which means that, in 90% of times, the proportion of underpaid nurses wil be between 0.1085 and 0.1915.

(ii) For the difference in proportions:

± z.

The proportion for the second hospital is = 0.12 and, since it is the same confidence interval, z = 1.645.

Calculating:

(0.15-0.12) ± 1.645.

0.03 ± 1.645*0.0389

0.03 ± 0.0641

The 90% confidence interval for the difference in proportions of nurses being underpaid is between 0.0341 and 0.0941

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743