Box A contains 5 dark chocolates and 10 milk chocolates. Box B contains 12
dark chocolates and 12 milk chocolates.
Craig picks a box at random and then
takes out one chocolate at random.
If he chooses box A, what is the probability
he chooses a milk chocolate?
% (1 d. p.)

Step-by-step explanation:

The probability of picking box A;

P(A) = 1/2

Box A has 5 dark chocolates and 10 milk chocolates.

The probability of picking a milk chocolate from box A;

P(milk in A) = =

P(A) and P(milk in A) = × =

$53.50

step-by-step explanation:

you have to subtract the amount of money chuck earned ($72.50) by the cost of the gas for the mower ($11.25) and the new string for the trimmer he bought ($7.75).

72.50-11.25=61.25

and then subtract $61.25 by the second thing he bought (the new string for the trimmer)

61.25-7.75=53.5

so in total it's $53.50 (53 dollars and 50 cents)

answer: approximately 206 bones

i hope this u out a branlist and a would be greatly appreciated :