Classify the function as linear or quadratic and identify the quadratic, linear, and constant terms. y=(3x+4)(-2x-3)

And since the higher exponent for the x term is 2 we can classify the equation  as quadratic

Quadratic term: -6

Linear term: -17

Constant term: -12

Step-by-step explanation:

For this problem we have the following equation:

And we can distribute the terms and we got:

And solving we got:

And since the higher exponent for the x term is 2 we can classify the equation  as quadratic

Quadratic term: -6

Linear term: -17

Constant term: -12

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3