THIS WORTH 50 POINTS!

Step-by-step explanation:

Let x represent the number of cases of 16-oz cups produced.

Let y represent the number of cases of 20-oz cups produced.

The limitation imposed by available production time is ...

  x + y ≤ 15·8 = 120 . . . . maximum number of cases produced in a day

The limitation imposed by raw material is ...

  14x +18y ≤ 1800 . . . . . maximum amount of resin used in a day

__

The point of intersection of the boundary lines for these inequalities can be found using substitution:

  14(120- y)+18y = 1800

  4y = 120 . . . . . subtract 1680, simplify

  y = 30

  x = 120 -30 = 90

This solution represents the point at which production will make maximal use of available resources. It is one boundary point of the "feasible region" of the solution space.

__

The feasible region for the solution is the doubly-shaded area on the graph of these inequalities. It has vertices at ...

  (x, y) = (0, 100), (90, 30), (120, 0)

The profit for each of these mixes of product is ...

  (0, 100): 25·0 +20·100 = 2000

  (90, 30): 25·90 +20·30 = 2850 . . . . uses all available resources

  (120, 0): 25·120 +20·0 = 3000 . . . . maximum possible profit

The family can maximize their profit by producing only 16-oz cups at 120 cases per day.

90 16-oz cases and 30 20-oz cases will maximize resin and time use

120 16-oz cases will maximize profit

Step-by-step explanation:

(a) the volume of the cone is 20/3 in3

hence, option a is correct.

false

step-by-step explanation: