3/4, 1, 4/3, 16/9,... which of the following are recursive formulas for the nth term of the following geometric sequence?

nth term of geometric sequence = a(n) =

Step-by-step explanation:

nth term of geometric sequence = a(n)

nth term of geometric sequence = a(n) =

Where,

a =  first term

r = common ratio

n = number of term

So,

GP: 3/4, 1, 4/3, 16/9

a = 3/4

r = 1 / [3/4] = 4/3

n = n

nth term of geometric sequence = a(n) =

nth term of geometric sequence = a(n) =

c - they will have the same distribution

step-by-step explanation:

this is the only one that could make sense. : )

answer:

a=9

step-by-step explanation: lmk if you need a explanation