The slope-intercept form of the equation of a line that passes through point (–3, 8) is y =- 2 /3x +8 . What is the point-slope form of the equation for this line? y – 3 = –2/3 (x + 8) y + 3 = -2/3 (x - 8) y + 8 = - 2/3 (x - 3) y - 8 = -2/3 (x + 3 )

y - 8 = - (x + 3)

Step-by-step explanation:

y = - x + 8 ← is in slope- intercept form with slope m = -

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = - and (a, b) = (- 3, 8), thus

y - 8 = - (x - (- 3)), that is

y - 8 = - (x + 3)

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm