Onyango is now three times as old as his daughter and four times as old as his son. Eight years from now, Onyango’s age will be twelve years more than the sum of the ages of his son and daughter. Find their present ages.

Brainliest please

50years is their ages now

Step-by-step explanation:

onyango= 3a

daughter= let it be a

son= he is 4 times less than his father, 3/4a

8years

8+3a+a+8+3/4a+a

a+8+3/4a+a

7/4+1 = 8/4a+8 + 12y 20= 8/4a = 40years is the father 8 years later, so his present age is 40-8

32y= father now

daughter= 1/3×32=10years

son= 1/4×32= 8yrs

add 32+10+8= 50years

step-by-step explanation:

i think you should think about the question and not look online.

i think asking google will you get the answer to that question