Determine all numbers at which are function Continuous.. f(x)={
x^2 + 5x - 36/
x^2 + 8x - 9
if x≠-9
if x= -9}
a.
continuous at every real number except x = 1 and x = -9
b. continuous at every real number except x = -9
c. continuous at every real number except x = 1
d. continuous at every real number except x = -9 and x = 4

For this case we have this function:

We can factor the denominator and we got:

And since we can't divide by 0 then the value of x can't be 1 or -9 so then the best answer for this case would be:

Continuous at every real number except x=1 and x=-9

Step-by-step explanation:

For this case we have this function:

We can factor the denominator and we got:

And since we can't divide by 0 then the value of x can't be 1 or -9 so then the best answer for this case would be:

Continuous at every real number except x=1 and x=-9

7

step-by-step explanation:

the answer would be 7

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.