The rectangle has an area of 60 square feet. Find its dimensions (in ft). (x + 4) feet smaller value ft larger value ft

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The rectangle has an area of 60 square feet. Find its dimensions (in ft) if the length of the rectangle is 4 ft more than its widh.

smaller value ___________________ ft

larger value ____________________ ft

Smaller value = 6 ft

Larger value = 10 ft

Step-by-step explanation:

Recall that the area of a rectangle is given by

Where W is the width and L is the length of the rectangle.

It is given that the rectangle has an area of 60 square feet.

It is also given that the length of the rectangle is 4 ft more than its width

Substitute into the above equation

So we are left with a quadratic equation.

We may solve the quadratic equation using the factorization method  

So,

Since width cannot be negative, discard the negative value of W

The length of the rectangle is  

Therefore, the dimensions of the rectangle are

Smaller value = 6 ft

Larger value = 10 ft

Verification:

Hence verified.

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

no association

step-by-step explanation:

if you have eyes and you can use them efficiently you can see that it just looks like random dots like do a line of best fit and like they're so spread out it's such a weak association you might as well consider it nonexistent