A particle is moving with the given data. Find the position of the particle. a(t) = 2t + 5, s(0) = 6, v(0) = −5

Position of the particle is :

Step-by-step explanation:

Given information:

The particle is moving with an acceleration that is function of:

To find the expression for the position of the particle first integrate for the velocity expression:

AS:

Where, is the initial velocity.

Noe, if we tale the ,

So, the velocity equation can be written as:

Now , For the position of the particle we need to integrate the velocity equation :

As,

Position:

Where, is the initial position of the particle.

So, we put the value and get the position of the particle.

Hence, Position of the particle is :

.

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The position of the particle is described by

Step-by-step explanation:

The position function is obtained after integrating twice on acceleration function, which is:

,

Velocity

Where is the initial velocity.

If , the particular solution of the velocity function is:

Position

Where is the initial position.

If , the particular solution of the position function is:

your answer would be 10x - 1

24/56=hx^7

step-by-step explanation: