Find the dimensions of a right circular cylinder of maximum volume that can be inscribed in a sphere of radius 7.

The height of the right circular cylinder is 14/√3 and its radius is 7√6/3.

Step-by-step explanation:

Check the attachment for the diagram.

The volume of a right circular cylinder =  πr²h

r is the radius of the cylinder

h is the height of the cylinder

V = πr²h... 1

From the diagram, we can use Pythagoras theorem on the right angled triangle to get r². From the triangle P² = r²+(h/2)²

P is the radius of the sphere.

P = 7

7² = r²+(h/2)²

r² = 49-(h/2)²... 2

Substituting equation 2 into 1:

V = π(49-(h/2)²)h

V = π(49h-h³/4)...3

To get the height h of the cylinder, we need to differentiate the volume of the cylinder with respect to h and equate to zero. i.e dV/dh = 0 since it's the maximum volume.

dV/dh = π(49-3h²/4)

0 = π(49-3h²/4)

Dividing both sides by π

0/π = π(49-3h²/4)/π

49-3h²/4 = 0

49 = 3h²/4

3h² = 49×4

3h² = 196

h² = 196/3

h = √196/√3

h = 14/√3

To get the radius of the cylinder, we will substitute h = 14/√3 into equation 2

r² = 49-(h/2)²

r² = 49-{(14/√3)/2}²

r² = 49-{14/2√3}²

r² = 49-(7/√3)²

r² = 49 - 49/3

r² = (147-49)/3

r² = 98/3

r = √98/√3

r = √49× √2/√3

r = 7√2/√3

r = 7√2/√3 × √3/√3

r = 7√6/3

The height of the right circular cylinders is 14/√3 and its radius is 7√6/3.

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.