(05.06A)The figure below shows the letter T and four of its transformed images—A, B, C, and D: A letter T is formed on the coordinate plane with endpoints negative 5 comma negative 1, negative 3 comma negative 1, and negative 4 comma negative 3. Figure A has endpoints negative 5 comma 3, negative 3 comma 3, and negative 4 comma 1. Figure B has endpoints negative 1 comma 2, negative 3 comma 2, and negative 2 comma 4. Figure C has endpoints 3 comma negative 1, 4 comma negative 3, and 5 comma negative 1. Figure D has endpoints 2 comma 1, 3 comma 3, and 4 comma 1. Which of the four images was formed by a reflection of the letter T? A B C D

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

chase is right because he already been to the swings and he know how far it will be to get there

step-by-step explanation:

answer: it is d

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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