Find factors of x³+12x²-19x= -20

No Factors

Step-by-step explanation:

Factors of 20 = ±1, ±2 , ±4 , ±5 , ±10 and ±20

±1, ±2 and ±3 are not the factors of given polynomial.

Putting x = 4 in the given polynomial

So, x = 4 is not a factor of p(x)

Putting x = -4 in the given equation

So, x = -4 in the given equation

Putting x = 5 in the given equation

So, x = 5 is not a factor of p(x)

Putting x = -5 in the given equation

So, x = -5 is not a factor of p(x)

Putting x = 10 in the given equation

So, x = 10 is not a factor of p(x)

Putting x = -10 in the given equation

So, x = -10 is not a factor of p(x)

Putting x = 20 in the given equation

So, x = 20 is not a factor of p(x)

Putting x = -20 in the given equation

So, x = -20 is not a factor of p(x)

From the above solution, we conclude that the given equation can not be factorized and thus, has no factors.

Step-by-step explanation:

Add 20 on both sides.

Add 67x and 44 on both sides.

Factor left side of the equation.

Subtract 67x and 44 on both sides.

Cannot be factored further.

This is a prime expression. A prime expression cannot be factored.

We cannot factor out x from the expression, there are no factors.