Which term of the AP:3,15,27, 39,will be 132 more than its 54th term

n=65th term

Step-by-step explanation:

AP:3,15,27,39

From the AP

a=3

a+d=15

a+2d=27

3+d=15 (1)

3+2d=27 (2)

Subtract (1) from (2)

We have,

2d-d=27-15

d=12

54th term=a+(n-1)d

=3+(54-1)12

=3+(53)12

=3+636

=639

The term is 132 more than the 54th term

132+54th term

=132+639

=771

Find the term

771=a+(n-1)d

771=3+(n-1)12

771-3=12n-12

768=12n-12

768+12=12n

780=12n

n=780/12

=65

n=12

The term which is 132 more than the 54th term is the 65th term