Find the zeros of g(x) = x3 + x2 – 9x – 9

The zeros are -1,-3, and 3

Hope this helps

let g[x]=0

then0=x3−x2-9x+9

rewrite it as x3−x2−9x+9=0

by factorising it becomes

(x−1)(x+3)(x−3)=0

therefore

either x-1=0  OR x+3=0  OR  x-3=0

which becomes

x=1   OR   x=-ve3  OR  x=3

are the zeroes of the polynomial

hope this helps

step-by-step explanation: