A genetic experiment with peas resulted in one sample of offspring that consisted of 435 green peas and 163 yellow peas. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations

a

The  estimate for the percentage of yellow peas lie within the confidence interval  23.66%  and  30.83 %

b

Since the expected value for the estimate of the yellow peas lies between  the confidence interval it means that the given estimate  of yellow peas does not contradict the expectation

Step-by-step explanation:

From the question we are told that

       The number of green peas is  

        The number of  yellow peas is  

       The sample size is  

 The  sample proportion of the yellow peas is  

substituting values  

Given that the confidence level is  %

The level of significance is  %

    The critical values at this  level of significance is  obtained from the table of critical values as

Now the confidence interval is  mathematically evaluated as

substituting values  

So the 95%  confidence interval is  

      k = (  0.2366, 0.3083)

This mean that the estimate of the yellow peas(25%) lies between

             23.66%  and  30.83 %

Given that the expected value for the estimate of the yellow peas lies between  the confidence interval it means that the given estimate  of yellow peas does not contradict the expectation

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

ver más en -

step-by-step explanation: