An equilateral triangular plate with sides 8 m is submerged vertically in water so that the base is even with the surface. Express the hydrostatic force against one side of the plate as an integral and evaluate it.

Hydro static force is =18377 N

Step-by-step explanation:

The hydro static force is equals to the hydro static pressure times the area.

The hydro static pressure of a fluid increases as the depth of the fluid increases and the formula of it is given below.

Hydro static Pressure, P = d·g·ρ

Where, d is the depth of the object

g is the gravitational constant

ρ is the density of the fluid

Density of water   ρ =

=1000 kg/m^3 * 9.8m/s^2 which is √(3/2).a below the water level.

Side of the plate  x = 10 m

The hydrostatic force = the pressure at the center x the area ==18377 N

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