Where must the fulcrum be located if a 300-pound weight and a 450-pound weight balance when placed on each end of a 15-foot bar

9 foot.

Step-by-step explanation:

From the question given, we were told that a 300-pound weight and a 450-pound weight are placed on each end of a 15-foot bar.

The diagram illustrating the question can be seen on the attached photo.

Weight 1 (W1) = 300 pound

Weight 2 (W2) = 450 pound.

Distance to which the fulcrum must be placed in order to balance (d1) = x

Distance from the other side of the bar (d2) = 15 – x

W1d1 = W2d2

300 × x = 450 (15 – x)

Clear bracket

300x = 6750 – 450x

Collect like terms

300x + 450x = 6750

750x = 6750

Divide both side by the coefficient of x i.e 750

x = 6750/750

x = 9 foot.

Therefore, the fulcrum must be placed at 9 foot in order to balance the bar.

the arc length is found by finding the circumference of the full circle (2xpixradius) and then dividing by 4 to find just one quarter of the circle (90 degrees).