Problem number 26 of the Rhind Papyrus says: Find a quantity such that when it is added to StartFraction 1 Over 4 EndFraction of itself the result is a 15. The modern day equation that models this problem is x plus StartFraction 1 over 4 EndFraction x equals 15..

THIS IS THE COMPLETE QUESTION BELOW

Problem number 26 of the Rhind Papyrus says:

Find a quantity such that when it is added to ¼ of itself the result is 15.

The modern day equation that models this problem is x +

¼x = 15. What is the solution to the equation?

A) x = 10

B) x = 12

C) x = 15

D) x = 30

The quantity is X= 12

The solution is 12+ ¼(12)= 15

Step by step Explanation

Problem number 26 states " "

The question above can be represented as this,

x + ¼x = 15

Here we want to find the value of x in such a way that when that value is substitute in the expresion we have 15 as our answer,But here we can perform some manipulation, by saying

4/4x + ¼x = 15 eqn(1)

Even with this we can still get the above expression by saying

4/4x= x which means we're still correct.

Then the expresion eqn(1) can simplified as

5/4x = 15

If we multiply both sides by 4/5 we have

=(5/4x)×(4/5)

= 15×(4/5)

= (15/1)×(4/5)

X= 60/5

X = 12

The quantity is X= 12 and the solution is

12+ ¼(12)= 15

step-by-step explanation:

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm