Find the center, vertices, and foci of the ellipse with equation 2x2 + 6y2 = 12.

Center: (0,0)

Vertices: (±√6,0)

Foci: (±2,0)

Step-by-step explanation:

The equation of ellipse is given as:

2x² + 6y² = 12

2x²/12 + 6y²/12 = 12/12

x²/6 + y²/2 = 1

Write the denominators in squared forms:

x²/(√6)² + y²/(√2)² = 1

Thus, as denominator of x is greater than the denominator of y:

a = √6  ,  b = √2

As nothing is being added or subtracted to the x and y terms, Center is located at (0,0)

Vertices are located at (±a,0) which means vertices are located at (±√6,0)

Foci are located at (±c,0), where

c = √(a²-b²)

c = 2

Vertices : (±c , 0) = (±2,0)

6.9

step-by-step explanation:

simple math really

6 1/2 times 0.6 = 3.9

but if you are just doing 6 and not 6 1/2 then the answer is 3.6