2x-5y = 10 Solve for X
ok first i add 5y on both sides
so i get
2x = 10 + 5y
then i divided 2x on both sides
so i get
x = 10 + 5y / 2x
but how am i supposed to divide 10/2x and 5y/2x when they’re different variables??
someone please explain.

x = 5 + 5y/2

Step-by-step explanation:

When you get to 2x = 10 + 5y,

you should divide both sides with 2 only instead of 2x. Because if you divide 2x on both sides, the left side would only remain 1  (since 2x/2x = 1)

2x = 10 + 5y

x = (10 + 5y) / 2

x = 10/2 + 5y/2

x = 5 + 5y/2 .( or  5 + (5/2)y)

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

both equations and proportions are better.