For how many values of k will x² + kx + 12 factor?

  6

Step-by-step explanation:

We want to factor the trinomial into a product of binomials. In general, we have ...

  (x +a)(x +b) = x² +(a+b)x +ab

So, the values of "a" and "b" need to have a product of 12. There are 6 ways to do that:

  12 = 1·12 = 2·6 = 3·4 = (-1)(-12) = (-2)(-6) = (-3)(-4)

The values of k are the sums of these factors of 12, so are

  1+12 = 13

  2+6 = 8

  3+4 = 7

  -1-12 = -13

  -2-6 = -8

  -3-4 = -7

There are 6 possible integer values of k that will make the trinomial factorable in integers:

  k ∈ {-13, -8, -7, 7, 8, 13}

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation:

you have to put the graph on here with the question

step-by-step explanation: