The houses on a city block were valued at $172,000, $164,000, $142,000, $159,000, $191,000, $124,000, and $146,000, respectively. But a public
assessor has determined that the value of each house is actually $13,000
higher than previously thought. According to the public assessor, what is the
median value of the houses?
A. $159,000
B. $165,000
C. $172,000
D. $177,000

C. $172,000

Step-by-step explanation:

Calculation for the median value of the houses

The following data was given in the question:$172,000, $164,000, $142,000,

$159,000, $191,000, $124,000, and $146,000

The first step is to Arrange the above data in ascending order

$124,000,$142,000,$146,000,$159,000,

$164,000,$172,000,$191,000

Second step is to find the Median

The Median will be the mid value, which means that $159,000 is the mid value

Based on the information given in the question we were given that a public

assessor has determined that the value of each house is actually $13,000 higher than previously thought

Hence, the Median will be = $159,000+$13,000=$172,000

Therefore the median value of the houses will be $172,000

a

b

d

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204