A survey of 61,647 people included several questions about office relationships. Of the respondents, 26% reported that bosses scream at employees. Use a 0.05 significance level to test the claim that more than ¼ of people say that bosses scream at employees.

Step-by-step explanation:

n = 61,647, p = 0.26, q = 0.74

μ = p = 0.26

σ = √(pq/n) = 0.00177

At 0.05 significance, z = 1.96.

0.26 ± 1.96 × 0.00177

(0.257, 0.263)

0.25 is outside of the confidence interval, so we can conclude with 95% confidence that the proportion is greater than 0.25.

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation:

this may not be at all, but i use the same website you're using for school, and if i'm stuck doing one of these i try to look for it on the section.