Which line is perpendicular to the line whose equation is 5y + 6 = -3x?

B

Step by Step

5y + 6 = -3X

5y = -3X - 6

Y = -3/5X -6/5

Perpedicular is the flip of your slope so -3/5 becomes 5/3X

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

28

step-by-step explanation:

8+8+6+6