A new fertilizer was applied to the soil of 146 bean plants. 23% showed increased growth. Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer. Round all answers to 2 decimal places.

The significance level for this case would be and the critical value for this case would be:

The margin of error is given by:

And replacing we got:

And the margin of error for this case would be

Step-by-step explanation:

For this case we have the following dataset given:

represent the sample size

represent the estimated proportion of interest

represent the confidence level

The significance level for this case would be and the critical value for this case would be:

The margin of error is given by:

And replacing we got:

And the margin of error for this case would be

answer: add the !

step-by-step explanation: then we will answer

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.