A freight train leaves a station at noon traveling at 30 mph. A passenger train leaves 1 hour later traveling at 50 mph. At what time will the passenger train overtake the freight train? What is a reasonable answer? Do not solve.

A)2
1
2
hours
B)2:30 pm
C)45 mph
D)75 miles

t=2.5 hours after the freight train leaves the station they will meet.

Step-by-step explanation:

30t = 50 (t - 1)

30t = 50t - 50

30t - 50t = -50

-20t = -50

t= -50/-20

Therefor, t=2.5 hours after the freight train leaves the station they will meet.

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)