Consider the following. F(x) = x sec2 t dt π/3
(a) Integrate to find F as a function of x. F(x) =
(b) Demonstrate the Second Fundamental Theorem of Calculus by differentiating the result in part (a)
f(x) =

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

$113.42

i hope that is right.

step-by-step explanation: