An auto weighing 2,500 pounds is on a street inclined at 10 with the horizontal. Find the force necessary to prevent the car from rolling down the hill.

1931.7N

Step-by-step explanation:

We are told in the question that :

An auto ( a car) weighs = 2500 pounds

It s inclined at n horizontal Ange of 10°

We are asked to find the force that would prevents it from rolling down the street.

Since the unit for Force = Newton or kgm/s²

Step 1

Convert Weight in pounds to kg

1 pound = 0.453592kg

2500 pounds =

2500 pounds × 0.453592kg

= 1133.981kg

Step 2

Find the force that would prevents it from rolling down the street.

Force = Mass × Acceleration due to gravity × sin θ

Acceleration due to gravity = 9.81m/s

Force = 1133.981kg × 9.81 × sin 10°

Force = 1931.7237321 N

Approximately = 1931.7N

why can't you?

step-by-step explanation:

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.