Determine whether the given relation is an implicit solution to the given differential equation. Assume that the relationship does define y implicitly as a function x and use implicit differentiation. x2 − sin (x+y) = 1, dy dx =2 x sec (x+y) − 1

answer: 177/8

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

the furthest the dog can be is 508 meters away from the house, and the closest he can be is 492 meters away from the house.