In the diagram, AB a AD and BC DE. What additional information is necessary to prove that
A ABC A ADE, using the SAS congruence theorem?
5
B
с
3
2
AC = AE
AC AD
JA
-6 -5 -4 -3 -2 -1 / 1 2 3 4 5 6 x
ZABC > ZADE
ZBAC > ZDAE
-3
D4
-5+
E
-6