Pls ppl answer dis question PLS PLS PLS No scaming pls
4√3 x^2+5x-2√3

\the zeroes are (2√3)/ 3, (√3)/4,

or -1.15, 0.43 to the nearest hundredth.

Step-by-step explanation:

I am assuming you want to find the zeroes of this function:

4√3 x^2+5x-2√3 = 0

Using the quadratic formula:

x = [ -5 +/- √((5)^2 - 4 * 4√3  * -2√3) ]  / (2 * 4√3 )

=  ( - 5 +/- √(25 - (-32*3)) / 8√3

= (-5 +/- √ 121) / 8√3

= (-5 - 11) / 8√3 or  (-5 + 11) / 8√3

=  -16/8√3 or 6/8√3

= -16√3/ 24 or  6√3 / 24

= -2√3/ 3 or √3/4.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

c.

step-by-step explanation:

simple you would first have to get   a negative number where as 1 to be multiplied by 24 and then you would have to multiply 6 time 4 and then repeat that process until you reach your term