The image of ΔABC after a reflection across Line E G is ΔA'B'C'. 2 triangles are shown. Line E G is the line of reflection. Line segment D D prime has a midpoint at point F. Line segment C C prime has a midpoint at point G. Points B and B prime share a point. Which triangle must be a right triangle and why? ΔA'B'C' is right because it is the image of ΔABC. ΔADC is right because AA' intersects AC at A. ΔBCC' is right because B lies of the line of reflection. ΔBGC is right because Line E G is perpendicular-to CC'.

  ΔBGC is right because Line E G is perpendicular-to CC'

Step-by-step explanation:

The midpoints of the segments joining a triangle vertex with its reflected image will lie on the line of reflection. The segment will be perpendicular to the line of reflection.

In this scenario, a triangle will be right if it has a leg that is part of the segment joining reflected points, and a leg on the line of reflection. ΔBGC is such a triangle.

  ΔBGC is right

Comment on the problem statement

Point D came out of nowhere. A diagram would be most helpful.

k

step-by-step explanation:

domit

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages