John cut a paper square with a perimeter of 18 inches into two rectangles. The perimeter of one of the rectangles is 10 inches. What is the perimeter of the second rectangle?

13.5 inches

Step-by-step explanation:

Perimeter of the paper square = 18inches

Perimeter of a square = 4s

4s = 18 inches

s = 18/4 = 4.5 inches

Therefore, each side of the square = 4.5 inches.

When the square is cut into 2 rectangles,

The perimeter of one of the rectangles is 10 inches.

Perimeter of the second rectangle = 2L + 2W

Let the length of the rectangle (L) = one side of the square = 4.5 inches

Width of the Rectangle = Length of the square/2 = 4.5 inches/ 2 = 2.25

Perimeter of the second rectangle = 2(4.5) + 2(2.25)

= 9 + 4.5

= 13.5 inches

where are the images of the functions i can only see the question you typed.

step-by-step explanation:

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .