This is a trigonometry related problem, but I don't understand the question itself, finding the missing sides when it appears all the sides are given, as well as all the angles. Can someone help me out with this question? Thanks!

Problem 13

Explanation:

For any 45-45-90 triangle, the legs are the same length. One leg is 7, so the other leg is 7 as well. This means y = 7.

The hypotenuse of a 45-45-90 triangle is equal to sqrt(2) times the length of either leg. So that leads to 7*sqrt(2) being the hypotenuse. You can use the pythagorean theorem to solve 7^2+7^2 = x^2 to confirm that x = 7*sqrt(2)

Problem 14

Explanation:

The hypotenuse is 2*sqrt(3). Take half of this to get sqrt(3), which will be the length of the short leg y. So y = sqrt(3)

Multiply the short leg's length with sqrt(3) to get the length of the long leg

In other words,

long leg = (short leg)*sqrt(3)

long leg = sqrt(3)*sqrt(3)

long leg = sqrt(3*3)

long leg = sqrt(9)

long leg = 3

Therefore, x = 3

All of this applies to 30-60-90 triangles only. Like with problem 13, if you know two sides of a right triangle, you can use the pythagorean theorem to solve for the third missing side.

step-by-step explanation: step 3 should really go to step seven, but anyway never mind.

1 ∠oln ≅ ∠lno

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.