The projectile motion of an object can be modeled using h(t) = gt2 + v0t + h0, where g is the acceleration due to gravity, t is the time since launch, h(t) is the height of the projectile after time t, v0 is the initial velocity, and h0 is the initial height. The acceleration due to gravity is –9.8 m/s2. An object is launched at an initial velocity of 20 meters per second and an initial height of 60 meters. Which solution can be simplified to determine when the object will hit the ground? t = t = t = t =

parallel and congruent

step-by-step explanation:

the movement of translation is linear.   these have the same translation because you are using the same rule for each point of the triangle so you will see the same slope being used to get from a point on the triangle to its image.

same slope!   you should think parallel when you see those 2 word together (well unless it's the same line but it can't be because we are coming from different points here)

congruent! because each point is being moved the same distance.

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2

both equations and proportions are better.

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph