The height, h, in feet of a golf ball above the ground after being hit into the air is given by the equation, h = -16t 2 + 64t, where t is the number of seconds elapsed since the ball was hit. How many seconds does it take for the golf ball to hit the ground? It will take seconds for the ball to hit the ground.

4 seconds.

Step-by-step explanation:

The given equation is

where, h is height in feet of a golf ball above the ground after being hit into the air and t is the number of seconds elapsed since the ball was hit.

We need to find the time for the ball to hit the ground.

At ground level the height of ball is 0, i.e., h=0.

Using zero product property, we get

Therefore, it will take 4 seconds for the ball to hit the ground.

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.