There are 10 sweets in a bag. 4 are red, 2 are green, 3 are yellow and 1 is purple.



A sweet is chosen at random from the bag.

Here is a probability scale:

B C

a) Which letter shows the probability of choosing a yellow sweet?

b) Which letter shows the probability of choosing a sweet that is not orange?

Wenn

See Explanation Below

Step-by-step explanation:

Given

Total Sweets = 10

Red = 4

Green = 2

Yellow = 3

Purple = 1

Required

a & b

The question is not properly presented; however the solution is as follows;

A.

Let P(Yellow) represent the probability of selecting a yellow sweet and n(Yellow) represent the number of Yellow sweets;

So, whichever letter that shows or is the probability of choosing a yellow sweet

B.

Let P(Orange) represent the probability of selecting an orange sweet and n(Orange) represent the number of orange sweets;

Since, there's no orange sweet in the bag;

In probability; opposite probabilities add up to 1;

Let P(Not\ Orange) represent the probability of choosing a sweet that is not orange

Substitute

So, whichever letter that shows 0 is the probability of choosing a sweet that is not orange

a, b, c, d are correct.

step-by-step explanation:

we have g(x) = 3 and are required to find which option is a translation of g(x).

now, 'translation' is a transformation which means to shift the function in any direction and the general form of translation is g(x) + k, where k is any real number.

so, according to the options we see that all are correct as they satisfy the general form of translation.

also, it can be seen from the graph below that the function g(x) = 3 is shifted from its position in all the four options.