A ladder is placed against a vertical wall at an angle of 45° to the horizontal. If the foot of the ladder is 2.5m away from the wall, how high up the wall does the ladder reach?

Forming a triangle using the 45 degree angle both the horizontal and vertical dimensions need to be identical.

The horizontal dimension is given as 2.5m , so the vertical dimension also has to be 2.5m.

Can calculate it as:

Tan(45) = vertical/ horizontal

Tan(45) = x/2.5

Tan(45) = 1

1 = x/2.5

X = 2.5/1

X = 2.5

for the first question it would be the second answer for the second question it would be the third answer and for the third question it would be the first answer

step-by-step explanation: