he graphed line shown below is y = 3 x minus 1. On a coordinate plane, a line goes through (0, negative 1) and (1, 2). Which equation, when graphed with the given equation, will form a system that has an infinite number of solutions? y + 1 = 3 x y = negative 3 x + 1 y = 3 x + 1 y minus 3 x = negative 3

y + 1 = 3x

Step-by-step explanation:

The graphed line is y = 3x - 1

The options given to us are

y + 1 = 3x

y = -3x + 1

y = 3x + 1

y - 3x = -3

Consider the first equation:

y + 1 = 3x

Substitute (0,-1) into the equation:

-1 + 1 = 3(0)

0=0

Substitute (1,2) into the equation:

2+1 = 3(1)

3 = 3

Thus the equation holds true for the given points.

Rearrange the equation

y + 1 = 3x

y = 3x - 1

As it is the same equation which was initially graphed, both of these lines will be same and overlap each other, resulting in infinite number of solution

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

step-by-step explanation:

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