Mathematics, 17.07.2020 07:01, teriateria
The system of equations is solved using the linear combination method. StartLayout 1st row 1st column one-half x + 4 y = 8 right-arrow 2nd column negative 2 (one-half x + 4 y = 8) right-arrow 3rd column negative x minus 8 y = negative 16 2nd row 1st column 3 x + 24 y = 12 right-arrow 2nd column one-third (3 x + 24 y = 12) right arrow x + 8 y = 4 with Bar Underscript 3rd row 3rd column 0 = negative 12 EndLayout What does 0 = −12 mean regarding the solution to the system? There are no solutions to the system because the equations represent parallel lines. There are no solutions to the system because the equations represent the same line. There are infinitely many solutions to the system because the equations represent parallel lines. There are infinitely many solutions to the system because the equations represent the same line.
Answers: 1
Mathematics, 22.06.2019 01:30, zariah10191101
What is the remainder when 3x^2-x-10 is divided by x-1 -6,-7,-8, or -9
Answers: 1
Mathematics, 22.06.2019 01:40, christinavelez26
Suppose we have a set of small wooden blocks showing the 26 letters of the english alphabet, one letter per block. (think of scrabble tiles.) our set includes 10 copies of each letter. we place them into a bag and draw out one block at a time. (a) if we line up the letters on a rack as we draw them, how different ways coukl we fill a rack of 5 letters? (b) now suppose we just toss our chosen blocks into a pile, and whenever we draw a letter we already have, we put it back in the bag and draw again. how many different piles of 5 blocks could result? possible? piles will contain at least one repeated letter? (c) if we draw out 5 blocks wit hout looking at them, how many different piles are (d) if we draw out 5 blocks without looking at them, how many of the possible 2. (4) consider the following formula. 12 give two different proofs, one using the factorial formulas and the other combina torial.
Answers: 3
The system of equations is solved using the linear combination method. StartLayout 1st row 1st colum...
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