What is the probability of getting a number less than 2 OR a prime number upon rolling a six-sided die?

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur.

Probability = expected outcome/total outcome

Since a six-sided die is rolled, the total outcome will be the total number of possible siedes a die contain {1, 2, 3, 4, 5, 6} i.e 6 elements

If a number less than 2 is gotten, the expected outcome will be {1} i.e 1 element.

Probability of getting a number less than 2 = 1/6

If a prime number is gotten, the outcome will be the elements {2, 3, 5} i.e 3 elements.

The probability of getting a prime number = 3/6 = 1/2

The probability of getting a number less than 2 OR a prime number upon rolling a six-sided die will be 1/6*1/2 = 1/18

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

answer: 2 and 1

step-by-step explanation: got this question