Write the equation of a line that is perpendicular to -2/7x+9 that passes through the point (4, -6)

the desired equation is y = (-7/2)x - 8

Step-by-step explanation:

Don't you mean y = -2/7x+9, or y = (2/7)x+9?   Any line perpendicular to this line has a slope of -7/2, the negative reciprocal of (2/7).

Start with the slope-intercept formula:

y = mx + b.  Substitute -6 for  y, 4 for x and -7/2 for m.  Then we have

-6 = (-7/2)(4) + b.   This reduces to -6 = -14 + b, so that b must be -8.

Thus, the desired equation is y = (-7/2)x - 8

answer

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step-by-step explanation: