Suppose the finishing times for cyclists in a race are normally distributed and have a known population standard deviation of 9 minutes and an unknown population mean. A random sample of 18 cyclists is talken and gives a sample mean of 146 minutes. Find the confidence interval for the population mean with a 99% confidence level. 0.10 0.05 0.025 0.005 0.01
1.282 1.645 1.960 2.326 2.576

The 99% confidence interval for the population mean is between 140.54 minutes and 151.46 minutes

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

So it is z with a pvalue of , so

Now, find the margin of error M as such

In which is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 146 - 5.46 = 140.54 minutes

The upper end of the interval is the sample mean added to M. So it is 146 + 5.46 = 151.46 minutes

The 99% confidence interval for the population mean is between 140.54 minutes and 151.46 minutes

7 ft 6 in means 7 1/2, because 6 in is 1/2 of a foot. 7 ft 8 in means 7 2/3 because 8 in is 2/3 of a foot. 23/3 = 7 2/3. 15/2 = 7 1/2.

23/3   *   15/2   = 57 1/2

step-by-step explanation:

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